Polar Decompositions in Finite Dimensional Indefinite Scalar Product Spaces: Special Cases and Applications

Author(s):  
Yuri Bolshakov ◽  
Cornelis V. M. van der Mee ◽  
André C. M. Ran ◽  
Boris Reichstein ◽  
Leiba Rodman
1997 ◽  
Vol 27 (4) ◽  
pp. 497-501 ◽  
Author(s):  
Yuri Bolshakov ◽  
Cornelis V. M. van der Mee ◽  
André C. M. Ran ◽  
Boris Reichstein ◽  
Leiba Rodman

1997 ◽  
Vol 261 (1-3) ◽  
pp. 91-141 ◽  
Author(s):  
Yuri Bolshakov ◽  
Cornelis V.M. van der Mee ◽  
AndréC.M. Ran ◽  
Boris Reichstein ◽  
Leiba Rodman

1998 ◽  
Vol 30 (4) ◽  
pp. 432-451 ◽  
Author(s):  
Cornelis V. M. van der Mee ◽  
André C. M. Ran ◽  
L. Rodman

1997 ◽  
Vol 18 (3) ◽  
pp. 752-774 ◽  
Author(s):  
Yuri Bolshakov ◽  
Cornelis V. M. van der Mee ◽  
André C. M. Ran ◽  
Boris Reichstein ◽  
Leiba Rodman

1980 ◽  
Vol 21 (1) ◽  
pp. 183-185
Author(s):  
C. K. Fong

Let A be a complex Banach algebra with unit 1 satisfying ∥1∥ = 1. An element u in A is said to be unitary if it is invertible and ∥u∥ = ∥u−1∥ = 1. An element h in A is said to be hermitian if ∥exp(ith)∥ = 1 for all real t; that is, exp(ith) is unitary for all real t. Suppose that J is a closed two-sided ideal and π: A → A/J is the quotient mapping. It is easy to see that if x in A is hermitian (resp. unitary), then so is π(x) in A/J. We consider the following general question which is the converse of the above statement: given a hermitian (resp. unitary) element y in A/J, can we find a hermitian (resp. unitary) element x in A such that π(x)=y? (The author has learned that this question, in a more restrictive form, was raised by F. F. Bonsall and that some special cases were investigated; see [1], [2].) In the present note, we give a partial answer to this question under the assumption that A is finite dimensional.


1961 ◽  
Vol 4 (3) ◽  
pp. 261-264
Author(s):  
Jonathan Wild

Let E be a finite dimensional vector space over an arbitrary field. In E a bilinear form is given. It associates with every sub s pa ce V its right orthogonal sub space V* and its left orthogonal subspace *V. In general we cannot expect that dim V* = dim *V. However this relation will hold in some interesting special cases.


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