On the exponential Diophantine equation $$(3pm^2-1)^x+(p(p-3)m^2+1)^y=(pm)^z$$ ( 3 p m 2 - 1 ) x + ( p ( p - 3 ) m 2 + 1 ) y = ( p m ) z
2016 ◽
Vol 74
(2)
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pp. 227-234
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2013 ◽
Vol 66
(2)
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pp. 193-200
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2011 ◽
Vol 87
(4)
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pp. 45-50
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2013 ◽
Vol 753-755
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pp. 3149-3152