adequate transversal
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2019 ◽  
Vol 56 (3) ◽  
pp. 323-334
Author(s):  
Aifa Wang

Abstract The aim of this paper is to study the congruences on abundant semigroups with quasi-ideal adequate transversals. The good congruences on an abundant semigroup with a quasi-ideal adequate transversal S° are described by the equivalence triple abstractly which consists of equivalences on the structure component parts I, S° and Λ. Also, it is shown that the set of all good congruences on this kind of semigroup forms a complete lattice.


2019 ◽  
Vol 17 (1) ◽  
pp. 43-51
Author(s):  
Xiangjun Kong ◽  
Pei Wang ◽  
Yonghong Wu

Abstract As the real common generalisations of both orthodox transversals and adequate transversals in the abundant case, the concept of refined generalised quasi-adequate transversal, for short, RGQA transversal was introduced by Kong and Wang. In this paper, an interesting characterization for a generalised quasi-adequate transversal to be refined is acquired. It is shown that the product of every two quasi-ideal RGQA transversals of the abundant semigroup S satisfying the regularity condition is a quasi-ideal RGQA transversal of S and that all quasi-ideal RGQA transversals of S compose a rectangular band. The related results concerning adequate transversals are generalised and enriched.


2011 ◽  
Vol 54 (3) ◽  
pp. 487-497 ◽  
Author(s):  
Xiangjun Kong

AbstractIn this paper, another relationship between the quasi-ideal adequate transversals of an abundant semigroup is given. We introduce the concept of a weakly multiplicative adequate transversal and the classic result that an adequate transversal is multiplicative if and only if it is weakly multiplicative and a quasi-ideal is obtained. Also, we give two equivalent conditions for an adequate transversal to be weakly multiplicative. We then consider the case when I and Λ (defined below) are bands. This is analogous to the inverse transversal if the regularity condition is adjoined.


2009 ◽  
Vol 25 (10) ◽  
pp. 1653-1664 ◽  
Author(s):  
Xiang Fei Ni ◽  
Yan Feng Luo ◽  
Hai Zhou Chao

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