partial latin square
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2019 ◽  
Vol 28 (5) ◽  
pp. 675-695 ◽  
Author(s):  
Lina J. Andrén ◽  
Carl Johan Casselgren ◽  
Klas Markström

AbstractAnn×npartial Latin squarePis calledα-dense if each row and column has at mostαnnon-empty cells and each symbol occurs at mostαntimes inP. Ann×narrayAwhere each cell contains a subset of {1,…,n} is a (βn,βn, βn)-array if each symbol occurs at mostβntimes in each row and column and each cell contains a set of size at mostβn. Combining the notions of completing partial Latin squares and avoiding arrays, we prove that there are constantsα,β> 0 such that, for every positive integern, ifPis anα-densen×npartial Latin square,Ais ann×n (βn, βn, βn)-array, and no cell ofPcontains a symbol that appears in the corresponding cell ofA, then there is a completion ofPthat avoidsA; that is, there is a Latin squareLthat agrees withPon every non-empty cell ofP, and, for eachi,jsatisfying 1 ≤i,j≤n, the symbol in position (i,j) inLdoes not appear in the corresponding cell ofA.



10.37236/5675 ◽  
2016 ◽  
Vol 23 (2) ◽  
Author(s):  
Jaromy Kuhl ◽  
Michael W. Schroeder

Let $r,c,s\in\{1,2,\ldots,n\}$ and let $P$ be a partial latin square of order $n$ in which each nonempty cell lies in row $r$, column $c$, or contains symbol $s$. We show that if $n\notin\{3,4,5\}$ and row $r$, column $c$, and symbol $s$ can be completed in $P$, then a completion of $P$ exists. As a consequence, this proves a conjecture made by Casselgren and Häggkvist. Furthermore, we show exactly when row $r$, column $c$, and symbol $s$ can be completed.



2008 ◽  
Vol 308 (13) ◽  
pp. 2830-2843
Author(s):  
Nicholas Cavenagh ◽  
Diane Donovan ◽  
Abdollah Khodkar ◽  
John Van Rees


10.37236/780 ◽  
2008 ◽  
Vol 15 (1) ◽  
Author(s):  
Peter Adams ◽  
Darryn Bryant ◽  
Melinda Buchanan

It is shown that any partial Latin square of order at least six which consists of two filled rows and two filled columns can be completed.



2004 ◽  
Vol 32 (5) ◽  
pp. 479-484 ◽  
Author(s):  
Carla P. Gomes ◽  
Rommel G. Regis ◽  
David B. Shmoys


10.37236/1629 ◽  
2002 ◽  
Vol 9 (1) ◽  
Author(s):  
Ian M. Wanless

We define a $k$-plex to be a partial latin square of order $n$ containing $kn$ entries such that exactly $k$ entries lie in each row and column and each of $n$ symbols occurs exactly $k$ times. A transversal of a latin square corresponds to the case $k=1$. For $k>n/4$ we prove that not all $k$-plexes are completable to latin squares. Certain latin squares, including the Cayley tables of many groups, are shown to contain no $(2c+1)$-plex for any integer $c$. However, Cayley tables of soluble groups have a $2c$-plex for each possible $c$. We conjecture that this is true for all latin squares and confirm this for orders $n\leq8$. Finally, we demonstrate the existence of indivisible $k$-plexes, meaning that they contain no $c$-plex for $1\leq c < k$.



Author(s):  
C. C. Lindner ◽  
C. A. Rodger

AbstractIn 1960, Trevor Evans gave a best possible embedding of a partial latin square of order n in a latin square of order t, for any t ≥ 2n. A latin square of order n is equivalent to a 3-cycle system of Kn, n, n, the complete tripartite graph. Here we consider a small embedding of partial 3k-cycle systems of Kn, n, n of a certain type which generalizes Evans' Theorem, and discuss how this relates to the embedding of patterned holes, another recent generalization of Evans' Theorem.



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