On absolute summability of Fourier integrals with multipliers
We obtain the conditions for function that generates functional method and for the multiplier $\mu(y)$ that are sufficient for absolute summability of$$\int\limits_0^{\infty} \mu (y) B(y, t) dy$$where $\int\limits_0^{\infty} B(y, t) dy$ is the Fourier integral of a function $f(t) \in L_{(-\infty, \infty)}$.
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