17.—An Upper Bound for the Largest Zero of Hermite's Function with Applications to Subharmonic Functions
1976 ◽
Vol 75
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pp. 183-197
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SYNOPSISLetbe Hermite's function of order λ and let h = h(λ) be the largest real zero of Hλ(t). SetIn this paper we establish the inequalitywhereEquality holds for S = ½. The result is also fairly accurate as S→0 and S→1. The proof is analytical except in the ranges −1·1 ≦ h ≦ −0·1 and where the argument is concluded by means of a computer.The following deduction is made elsewhere [2, Theorem A]. If u(x) is subharmonic in Rm(m ≧ 2) and the set E where u(x) > 0 has at least k components, where k ≧ 2, then the order ρ of u(x) is at least ϕ(1/k). In particular, if ρ < 1, E is connected. This result fails for ρ = 1.
2011 ◽
Vol 54
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pp. 685-693
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1953 ◽
Vol 49
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pp. 59-62
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1970 ◽
Vol 22
(3)
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pp. 569-581
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1975 ◽
Vol 17
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pp. 759-761
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1968 ◽
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pp. 499-501
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1998 ◽
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pp. 373-386
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1970 ◽
Vol 13
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pp. 115-118
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1985 ◽
Vol 97
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pp. 321-324
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