Quantum-noise quenching in the correlated spontaneous-emission laser as a multiplicative noise process. I. A geometrical argument

1988 ◽  
Vol 37 (4) ◽  
pp. 1261-1269 ◽  
Author(s):  
W. Schleich ◽  
M. O. Scully
2003 ◽  
Vol 17 (22n24) ◽  
pp. 4123-4138 ◽  
Author(s):  
Wing-Shun Lam ◽  
Parvez N. Guzdar ◽  
Rajarshi Roy

The dynamical behavior of power dropouts in a semiconductor laser with optical feedback, pumped near threshold current, is strongly influenced by quantum noise. This is clearly demonstrated by experiments with modulations on the pumping current or the feedback strength. For the cases without modulation and with only current modulation, the dropouts occur randomly. However the feedback strength modulation locks the dropout events periodically. By numerically modeling these three cases using the Lang–Kobayashi equations with a stochastic term to take into account spontaneous emission noise, it is shown that the observed behavior of the dropouts can be readily reproduced for all three cases. Noise plays a signifcant role in explaining the observed dropout events. A simple explanation of the observed dropout phenomenon is presented, based on the adiabatic motion of the ellipse formed by the steady state solutions of the rate equations due to slow time modulations of the injection current or the feedback strength.


2010 ◽  
Vol 09 (01) ◽  
pp. 9-18 ◽  
Author(s):  
PIOTR GAWRON

The influence of spontaneous emission channel and generalized Pauli channel on quantum Monty Hall Game is analyzed. The scheme of Flittney and Abbott is reformulated using the formalism of density matrices. Optimal classical strategies for given quantum strategies are found. The whole presented scheme illustrates how quantum noise may change the odds of a zero-sum game.


1988 ◽  
Vol 60 (18) ◽  
pp. 1832-1835 ◽  
Author(s):  
Marlan O. Scully ◽  
K. Wódkiewicz ◽  
M. S. Zubairy ◽  
J. Bergou ◽  
Ning Lu ◽  
...  

2018 ◽  
Vol 26 (9) ◽  
pp. 11587 ◽  
Author(s):  
Haisong Jiao ◽  
Tao Pu ◽  
Jilin Zheng ◽  
Hua Zhou ◽  
Lin Lu ◽  
...  

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