scholarly journals Optimization for the Determination of Hydrogen Peroxide in River Water Based on the Fenton Reaction with Terephthalate

2019 ◽  
Vol 68 (2) ◽  
pp. 125-131 ◽  
Author(s):  
Ryuta UEKI ◽  
Ryota KATO ◽  
Yoshitaka IMAIZUMI ◽  
Yoko IWAMOTO ◽  
Waqar A. JADOON ◽  
...  
2008 ◽  
Vol 627 (2) ◽  
pp. 270-276 ◽  
Author(s):  
Emmanuel F. Olasehinde ◽  
Shinya Makino ◽  
Hiroaki Kondo ◽  
Kazuhiko Takeda ◽  
Hiroshi Sakugawa

2018 ◽  
Vol 34 (4) ◽  
pp. 459-464 ◽  
Author(s):  
Kazuhiko TAKEDA ◽  
Hitoshi NOJIMA ◽  
Kengo KUWAHARA ◽  
Russel Chrispine CHIDYA ◽  
Adeniyi Olufemi ADESINA ◽  
...  

The Analyst ◽  
2015 ◽  
Vol 140 (22) ◽  
pp. 7650-7656 ◽  
Author(s):  
Hao-Hua Deng ◽  
Gang-Wei Wu ◽  
Dong He ◽  
Hua-Ping Peng ◽  
Ai-Lin Liu ◽  
...  

In this study, we used Fenton reaction-stimulated fluorescence quenching of N-acetyl-l-cysteine-protected gold nanoclusters as a reporter system for the determination of H2O2, glucose, and catalase.


2013 ◽  
Vol 14 (1) ◽  
pp. 48-54

This work is first report showed that supported TiO2 NPs on alumina could act catalytic activity on peroxyoxalate chemiluminescence system. In this work the catalytic effect of supported Titanium dioxide nanoparticles (TiO2 NPs) on the trichloroperoxy oxalate – hydrogen peroxide (PO-CL) reaction is investigated. Supported TiO2 nanoparticles exhibited the better CL catalysis activity than SnO and Carbon nanotubes. Supported TiO2 nanoparticles catalyze the chemiluminescence reaction between TCPO (bis-(2,4,6-trichlorophenyl) oxalate) and H2O2 and produce a strong CL signal in the presence of triazinyl dye derivative as fluorophore. The CL signal intensity was linear with the hydrogen peroxide concentration in the range of 5 to 1000 nmol ml-1 with a detection limit of 1.2 nmol ml-1 and regression coefficient was 0.992 (n=4). The relative standard deviations for measurement of 300 and 500 nmol ml-1 hydrogen peroxide were 2.2 and 3.4%, respectively(n=4). Hydrogen peroxide concentration in river water was 8.7 nmol ml-1 with RSD=5.4%(n=3).


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