Abstract
For the period T(α) of a simple pendulum with the length L and the amplitude (the initial elongation) α ∈ (0, π), a strictly increasing sequence Tn
(α) is constructed such that the relations
T
1
(
α
)
=
2
L
g
π
−
2
+
1
ϵ
ln
1
+
ϵ
1
−
ϵ
+
π
4
−
2
3
ϵ
2
,
T
n
+
1
(
α
)
=
T
n
(
α
)
+
2
L
g
π
w
n
+
1
2
−
2
2
n
+
3
ϵ
2
n
+
2
,
$$\begin{array}{c}
\displaystyle
T_1(\alpha)=2\sqrt{\frac{L}{g}}\left[\pi-2+\frac{1}{\epsilon}
\ln\left(\frac{1+\epsilon}{1-\epsilon}\right)+\left(\frac{\pi}{4}-\frac{2}{3}\right)\epsilon^2\right],\\
\displaystyle T_{n+1}(\alpha)=T_n(\alpha)+2\sqrt{\frac{L}{g}}\left(\pi w_{n+1}^2
- \frac{2}{2n+3}\right)\epsilon^{2n+2},
\end{array}$$
and
0
<
T
(
α
)
−
T
n
(
α
)
T
(
α
)
<
2
ϵ
2
n
+
2
π
(
2
n
+
1
)
,
$$\begin{array}{}
\displaystyle
0 \lt \frac{T(\alpha)-T_n(\alpha)}{T(\alpha)} \lt \frac{2\epsilon^{2n+2}}{\pi(2n+1)}\,,
\end{array}$$
holds true, for α ∈ (0, π), n ∈ ℕ,
w
n
:=
∏
k
=
1
n
2
k
−
1
2
k
$\begin{array}{}
\displaystyle
w_n:=\prod_{k=1}^n\frac{2k-1}{2k}
\end{array}$
(the nth Wallis’ ratio) and ϵ = sin(α/2).