On cardinalities and compact closures
<div class="page" title="Page 1"><div class="layoutArea"><div class="column"><p><span>We show that there exists a Hausdorff topology on the set </span><span>R </span><span>of real numbers such that a subset </span><span>A </span><span>of </span><span>R </span><span>has compact closure if and only if </span><span>A </span><span>is countable. More generally, given any set </span><span>X </span><span>and any infinite set </span><span>S</span><span>, we prove that there exists a Hausdorff topology on </span><span>X </span><span>such that a subset </span><span>A </span><span>of </span><span>X </span><span>has compact closure if and only if the cardinality of </span><span>A </span><span>is less than or equal to that of </span><span>S</span><span>. When we attempt to replace “than than or equal to” in the preceding statement with “strictly less than,” the situation is more delicate; we show that the theorem extends to this case when </span><span>S </span><span>has regular cardinality but can fail when it does not. This counterexample shows that not every bornology is a bornology of compact closure. These results lie in the intersection of analysis, general topology, and set theory. </span></p></div></div></div>